zipWith() function

返回通过将 f 应用于 Iterable/AsyncIterable 中每个相同位置的对而从两个提供的 Iterable/AsyncIterable 得到的 Iterable/AsyncIterable。

Signature:

declare function zipWith<A, B, C>(
  f: (a: A, b: B) => C,
  iterable1: Iterable<A>,
  iterable2: Iterable<B>,
): IterableIterator<C>;

Example

const iter = zipWith((a, b) => [a, b], [1, 2, 3], ["a", "b", "c"]);
iter.next(); // {value: [1, 'a'] , done: false}
iter.next(); // {value: [2, 'b'] , done: false}
iter.next(); // {value: [3, 'c'] , done: false}
iter.next(); // {value: undefined , done: true}

Open Source Code