pluck() function
제공된 Iterable/AsyncIterable의 모든 객체에서 동일한 이름의 속성을 추출하여 Iterable/AsyncIterable을 반환합니다.
Signature:
typescript
declare function pluck<O extends object, K extends keyof O>(
key: K,
iterable: Iterable<O>,
): IterableIterator<O[K]>;Example
ts
const iter = pluck("age", [{ age: 21 }, { age: 22 }, { age: 23 }]);
iter.next(); // {done:false, value: 21}
iter.next(); // {done:false, value: 22}
iter.next(); // {done:false, value: 23}
// with pipe
pipe([{ age: 21 }, { age: 22 }, { age: 23 }], pluck("age"), toArray); // [21, 22 ,23]
// if you want to use asynchronous callback
await pipe(
Promise.resolve([{ age: 21 }, { age: 22 }, { age: 23 }]),
toAsync,
pluck("age"),
toArray,
); // [21, 22 ,23]
// with toAsync
await pipe(
[
Promise.resolve({ age: 21 }),
Promise.resolve({ age: 22 }),
Promise.resolve({ age: 23 }),
],
toAsync,
pluck("age"),
toArray,
); // [21, 22 ,23]