append() function
与えられた iterable の内容の後に、与えられた要素が続く Iterable/AsyncIterable を返します。
Signature:
typescript
declare function append<A, B extends Iterable<A> | AsyncIterable<Awaited<A>>>(
a: A,
): (iterable: B) => ReturnIterableIteratorType<B, Awaited<A>>;Example
ts
const iter = append(4, [1, 2, 3]);
iter.next(); // {done: false, value: 1}
iter.next(); // {done: false, value: 2}
iter.next(); // {done: false, value: 3}
iter.next(); // {done: false, value: 4}
iter.next(); // {done: true, value: undefined}
// with pipe
pipe([1, 2, 3], append(4), toArray); // [1,2,3,4]
await pipe(Promise.resolve([1, 2, 3]), append(4), toArray); // [1, 2, 3, 4]
// with toAsync
await pipe(
[Promise.resolve(1), Promise.resolve(2), Promise.resolve(3)],
toAsync,
append(4),
toArray,
); // [1, 2, 3, 4]